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JEE Main20245 Apr 2024Evening ShiftPhysicsCurrent ElectricityActual

A galvanometer of resistance 100 when connected in series with 400 measures a voltage of upto 10 ~V . The value of resistance required to convert the galvanometer into ammeter to read upto 10 ~A is x 10⁻² . The value of x is :

Options

  1. A2
  2. B800
  3. C20
  4. D200

Correct answer

C. 20

Step-by-step solution

i _ g = 10 400+100 =20 10⁻³ ~A For ammeter Let shunt resistance = S aligned & i _ g R = ( i - i _ g ) S & 20 10⁻³ 100=10 ~S & ~S =20 10⁻² aligned

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