A wire of resistance 20 is divided into 10 equal parts, resulting...

A wire of resistance

20 \Omega

is divided into 10 equal parts, resulting pairs. A combination of two parts are connected in parallel and so on. Now resulting pairs of parallel combination are connected in series. The equivalent resistance of final combination is _____

\Omega

A wire of resistance 20 is divided into 10 equal parts, resulting pairs. A combination of two parts are connected in

Correct answer

Step-by-step solution

Each part has resistance

=2 \Omega

2 parts are connected in parallel so,

\mathrm{R}=1 \Omega

Now, there will be 5 parts each of resistance

1 \Omega

, they are connected in series.

\mathrm{R}_{\mathrm{eq}}=5 \mathrm{R}, \mathrm{R}_{\mathrm{eq}}=5 \Omega

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