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JEE Main20241 Feb 2024Evening ShiftPhysicsCurrent ElectricityActual

In an ammeter, 5 % of the main current passes through the galvanometer. If resistance of the galvanometer is G , the resistance of ammeter will be:

Options

  1. AG 20
  2. BG 199
  3. C199 G
  4. D200 G

Correct answer

A. G 20

Step-by-step solution

As potential drop across both branches would be the same, we get I S S = I g G 95 100 I S = 5 I 100 G ⇒ S = G 19 Now, resistance of ammeter will be R A = S G S + G = G 2 19 20 G 19 ⇒ R A = G 20

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