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JEE Main 20241 FebruaryMorning Shift
Exam
JEE Main
Year
2024
Date
1 February
Shift
Morning Shift
Subject
Physics
Chapter
Current Electricity

JEE Main 2024 · 1 February · Morning Shift · Physics · Current Electricity

The current in a conductor is expressed as I = 3 t ^ 2 + 4 t ^ 3 ,...

The current in a conductor is expressed as I=3t2+4t3I = 3{t}^{2} + 4{t}^{3}, where II is in Ampere and tt is in second. The amount of electric charge that flows through a section of the conductor during t=1st = 1s to t=2st = 2s is ____________ C.C .

Correct answer

0

Step-by-step solution

For variable current, integrate to get the total charge flown in a given interval.q=∫12idt=∫12(3t2+4t3)dtq = {∫}_{1}^{2}idt = {∫}_{1}^{2}\left(3{t}^{2} + 4{t}^{3}\right)dt

⇒q=(t3+t4)12{⇒ q = \left({t}^{3} + {t}^{4}\right)}_{1}^{2}

⇒q=22C⇒ q = 22C

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