A galvanometer has a resistance of 50Ω and it allows maximum...

A galvanometer has a resistance of

50Ω

and it allows maximum current of

5mA

. It can be converted into voltmeter to measure upto

100V

by connecting in series a resistor of resistance. A galvanometer has a resistance of 50Ω and it allows maximum current of 5mA . It can be converted into voltmeter to

A galvanometer has a resistance of 50Ω and it allows maximum current of 5mA . It can be converted into voltmeter to

Options

A $5975Ω$
B $20050Ω$
C $19950Ω$
D $19500Ω$

Correct answer

C. $19950Ω$

Step-by-step solution

If we connect a high resistance( $R$ ) in series with the galvanometer, it can be successfully converted into a voltmeter. Therefore,

A galvanometer has a resistance of 50Ω and it allows maximum current of 5mA . It can be converted into voltmeter to

Voltage drop across voltmeter:

$V = {I}_{g}\left({R}_{g} + R\right) ⇒ 100 = {I}_{g}\left(50 + R\right)$

$⇒ R = \dfrac{100}{5 \times {10}^{- 3}} - 50$

$= 19950Ω$

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