Equivalent resistance of the following network is ________ Ω .

Step-by-step solution

In the above diagram, 6 Ω is short circuit. Therefore, we can remove it. In the left part, 2 Ω and 2 Ω are in parallel combination, which will give us 1 Ω which again in turn is in series combination with the 2 Ω (adjacent to 3 Ω resistor), therefore net contribution of this part will be 1 Ω + 2 Ω = 3 Ω . Now, all three 3 Ω are in parallel across point A & B, therefore R e q = 3 × 1 3 = 1 Ω