Two cells are connected in opposition as shown. Cell E _ 1 is of 8V...

Two cells are connected in opposition as shown. Cell ${E}_{1}$ is of $8V$ emf and $2Ω$ internal resistance; the cell ${E}_{2}$ is of $2V$ emf and $4Ω$ internal resistance. The terminal potential difference of cell ${E}_{2}$ is ______ $V$ .

Correct answer

Step-by-step solution

Two cells are connected in opposition as shown. Cell E _ 1 is of 8V emf and 2Ω internal resistance; the cell E _ 2 is

Current in circuit, $I = \dfrac{8 - 2}{2 + 4} = \dfrac{6}{6} = 1A$

Applying Kirchhoff's law from $C$ to $B$ ,

${V}_{C} - 2 - 4 \times 1 = {V}_{B}$

$⇒ {V}_{C} - {V}_{B} = 6V$

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