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JEE Main 202430 JanuaryMorning Shift
Exam
JEE Main
Year
2024
Date
30 January
Shift
Morning Shift
Subject
Physics
Chapter
Current Electricity

JEE Main 2024 · 30 January · Morning Shift · Physics · Current Electricity

An electric toaster has resistance of 60Ω at room temperature (27 °...

An electric toaster has resistance of 60Ω60Ω at room temperature \left(27 ° C\right).Thetoasterisconnectedtoa. The toaster is connected to a220Vsupply.Ifthecurrentflowingthroughitreachessupply. If the current flowing through it reaches2 . 75A,thetemperatureattainedbytoasterisaround:(if, the temperature attained by toaster is around: (if\alpha = 2 \times {10}^{- 4} C - 1 ∘$ )

Options

  1. A694°C694 ° C
  2. B1235°C1235 ° C
  3. C1694°C1694 ° C
  4. D1667°C1667 ° C

Correct answer

C. 1694°C1694 ° C

Step-by-step solution

Resistance at 27°C27 ° C, RT=27=60Ω{R}_{T = 27} = 60Ω.

Final resistance, RT=2202.75=80Ω{R}_{T} = \dfrac{220}{2 . 75} = 80Ω.

Now, we can write R=R0(1+α\DeltaT)R = {R}_{0} ( 1 + \alpha\DeltaT )

⇒80=60[1+2×10−4(T−27)]⇒ 80 = 60\left[1 + 2 \times {10}^{- 4} ( T - 27 )\right]

⇒T≈1694°C⇒ T \approx 1694 ° C

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