In the given circuit, the current flowing through the resistance 20 Ω is 0 . 3 A , while the ammeter reads 0 . 9 A . The value of R 1 is _____ Ω .

Step-by-step solution

Given, i 1 = 0 . 3 A , i 1 + i 2 + i 3 = 0 . 9 A So, V AB = i 1 × 20 Ω = 0 . 3 × 20 V = 6 V i 2 = 6 V 15 Ω = 2 5 A Now, i 1 + i 2 + i 3 = 9 10 A ⇒ 3 10 + 2 5 + i 3 = 9 10 ⇒ 7 10 + i 3 = 9 10 ⇒ i 3 = 0 . 2 A So, i 3 × R 1 = 6 V ⇒ ( 0 . 2 ) R 1 = 6 ⇒ R 1 = 6 0 . 2 = 30 Ω