Different combination of 3 resistors of equal resistance R are...

The resistances can be calculated as

${R}_{A} = R + \dfrac{R}{2} = \dfrac{3R}{2}$

For second circuit

$\dfrac{1}{{R}_{B}} = \dfrac{1}{2R} + \dfrac{1}{R} = \dfrac{3}{2R} ⇒ {R}_{B} = \dfrac{2R}{3}$

For third circuit

${R}_{C} = \dfrac{R}{3}$

For fourth circuit

${R}_{D} = 3R$

The formula for power is given by $P = {I}^{2}R$.

Clearly,

${P}_{D} > {P}_{A} > {P}_{B} > {P}_{C}$