In the following circuit, the magnitude of current I 1 , is ______ A .

Step-by-step solution

The figure above shows the current and voltage at different points in circuit. Applying Kirchhoff's Junction law at A , x - ( y + 5 ) 1 + x - 2 2 + x - 0 2 = 0         . . . 1 Applying Kirchhoff's Junction law at B , y + 5 - x 1 + y - 0 1 + y - 2 1 = 0         . . . 2 Solving equation (1) and (2), we get x = 3 and y = 0 Now, at D junction I 1 = i 1 + i 2 ⇒ I 1 = y - 0 1 + x - 0 2 = 0 - 0 1 + 3 - 0 2 ⇒ I 1 = 1 . 5   A .