As shown in the figure, a network of resistors is connected to a battery of $24V$ with an internal resistance of $3Ω$ . The currents through the resistors ${R}_{4}$ and ${R}_{5}$ are ${I}_{4}$ and ${I}_{5}$ respectively. The values of ${I}_{4}$ and ${I}_{5}$ are:

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As shown in the figure, a network of resistors is connected to a battery of 24V with an internal resistance of 3Ω . The

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Correct answer: D. I _ 4 = (2)/(5)A and I _ 5 = (8)/(5)A

Equivalent resistance of circuit R _ eq = 3 + ((2 × 2)/(2 + 2)) + 2 + ((20 × 5)/(20 + 5)) + 2 = 12Ω Current through battery i = (24)/(12) = 2A Now, I _ 4 = R _ 5 R _ 4 + R _ 5 × 2 = (5)/(20 + 5) × 2 = (2)/(5)A and I _ 5 = i - I _ 4 = 2 - (2)/(5) = (8)/(5)A

As shown in the figure, a network of resistors is connected to a...

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