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JEE Main 202229 JuneEvening Shift
Exam
JEE Main
Year
2022
Date
29 June
Shift
Evening Shift
Subject
Physics
Chapter
Current Electricity

JEE Main 2022 · 29 June · Evening Shift · Physics · Current Electricity

Two resistors are connected in series across a battery as shown in...

Two resistors are connected in series across a battery as shown in figure. If a voltmeter of resistance 2000Ω2000Ω is used to measure the potential difference across 500Ω500Ω resister, the reading of the voltmeter will be _____ VV

Two resistors are connected in series across a battery as shown in figure. If a voltmeter of resistance 2000Ω is used

Correct answer

0

Step-by-step solution

Two resistors are connected in series across a battery as shown in figure. If a voltmeter of resistance 2000Ω is used

The voltmeter resistance is given to be 2000Ω2000Ω. The equivalent resistance in the given circuit is Req=500×20002000+500+600=1000Ω{R}_{eq} = \dfrac{500 \times 2000}{2000 + 500} + 600 = 1000Ω.

Now, current in the circuit is i=201000Ai = \dfrac{20}{1000}A.

Reading of the voltmeter will be, V=20−600×201000=8VV = 20 - 600 \times \dfrac{20}{1000} = 8V

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