The variation of applied potential and current flowing through a given wire is shown in figure. The length of wire is 31 . 4 cm . The diameter of wire is measured as 2 . 4 cm . The resistivity of the given wire is measured as x × 10 - 3 Ω cm . The value of x is _____ . [Take π = 3 . 14 ]

Step-by-step solution

Since, slope of V−I graph represents the resistance, so R = tan 45 ° = 1   Ω Now, resistance of wire is given by R = ρ L A So, resistivity of the wire is ρ = A R L = π r 2 R L = π 1 . 2 2 × 10 - 4 31 . 4 × 10 - 2 = 1 . 44 × 10 - 3   Ω   m = 144 × 10 - 3 Ω   cm