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JEE Main 202227 JuneEvening Shift
Exam
JEE Main
Year
2022
Date
27 June
Shift
Evening Shift
Subject
Physics
Chapter
Current Electricity

JEE Main 2022 · 27 June · Evening Shift · Physics · Current Electricity

In the given circuit 'a' is an arbitrary constant. The value of m...

In the given circuit 'a' is an arbitrary constant. The value of mm for which the equivalent circuit resistance is minimum, will be x2\sqrt{\dfrac{x}{2}}. The value of xx is _____ .

In the given circuit 'a' is an arbitrary constant. The value of m for which the equivalent circuit resistance is

Correct answer

0

Step-by-step solution

In the given circuit 'a' is an arbitrary constant. The value of m for which the equivalent circuit resistance is

Left part of the resistors are connected in parallel, hence R1=am3{R}_{1} = \dfrac{am}{3}.

Similarly, for the right part of the resistors we can write, R2=a2m{R}_{2} = \dfrac{a}{2m}.

Therefore, equivalent resistance will be,

R=am3+a2mR = \dfrac{am}{3} + \dfrac{a}{2m}

Differentiating both sides w.r.t mm to observe critical points, we get dRdm=a3+a(−1)2m2=0\dfrac{dR}{dm} = \dfrac{a}{3} + \dfrac{a\left(- 1\right)}{2{m}^{2}} = 0

⇒a3=a2m2⇒ \dfrac{a}{3} = \dfrac{a}{2{m}^{2}} ⇒m=32⇒ m = \sqrt{\dfrac{3}{2}}

Thus, x=3x = 3.

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