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JEE Main 202225 JuneEvening Shift
Exam
JEE Main
Year
2022
Date
25 June
Shift
Evening Shift
Subject
Physics
Chapter
Current Electricity

JEE Main 2022 · 25 June · Evening Shift · Physics · Current Electricity

Two cells of the same EMF E but different internal resistances r _...

Two cells of the same EMF EE but different internal resistances r1{r}_{1} and r2{r}_{2} are connected in series with an external resistance RR as shown in the figure. The terminal potential difference across, the second cell is found to be zero. The external resistance RR must then be:

Two cells of the same EMF E but different internal resistances r _ 1 and r _ 2 are connected in series with an external

Options

  1. Ar1r2{r}_{1}{r}_{2}
  2. Br1−r2{r}_{1} - {r}_{2}
  3. Cr2−r1{r}_{2} - {r}_{1}
  4. Dr1+r2{r}_{1} + {r}_{2}

Correct answer

C. r2−r1{r}_{2} - {r}_{1}

Step-by-step solution

Two cells of the same EMF E but different internal resistances r _ 1 and r _ 2 are connected in series with an external

In this question we have to find the Terminal potential difference of second cell, we are given the internal resistances of both the cells and an external resistance. Applying the following expression:-

V=E−ir2V = E - i{r}_{2}

⇒0=E−ir2⇒ 0 = E - i{r}_{2}

Applying the expression of current

0=E−(2Er1+r2+R)⋅r20 = E - \left(\dfrac{2E}{{r}_{1} + {r}_{2} + R}\right) \cdot {r}_{2}

⇒R=r2−r1⇒ R = {r}_{2} - {r}_{1}

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