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JEE Main 202225 JuneMorning Shift
Exam
JEE Main
Year
2022
Date
25 June
Shift
Morning Shift
Subject
Physics
Chapter
Current Electricity

JEE Main 2022 · 25 June · Morning Shift · Physics · Current Electricity

A teacher in his physics laboratory allotted an experiment to...

A teacher in his physics laboratory allotted an experiment to determine the resistance (G)\left(G\right) a galvanometer. Students took the observations for 13\dfrac{1}{3} deflection in the galvanometer. Which of the below is true for measuring value of GG?A teacher in his physics laboratory allotted an experiment to determine the resistance (G) a galvanometer. Students

Options

  1. A13\dfrac{1}{3} deflection method cannot be used for determining the resistance of the galvanometer.
  2. B13\dfrac{1}{3} deflection method can be used and in this case the GG equals to twice the value of shunt resistance(s).
  3. C13\dfrac{1}{3} deflection method can be used and in this case, the G equals to three times the value of shunt resistance(s).
  4. D13\dfrac{1}{3} deflection method can be used and in this case the GG value equals to the shunt resistance(s)

Correct answer

B. 13\dfrac{1}{3} deflection method can be used and in this case the GG equals to twice the value of shunt resistance(s).

Step-by-step solution

A teacher in his physics laboratory allotted an experiment to determine the resistance (G) a galvanometer. Students

If a large resistance RR is connected with a battery, then current will be approximately εR\dfrac{ε}{R}, and tt will remain almost constant.

In 1st{1}^{st} case, only (G)\left(G\right) is connected ⇒ig=i⇒ ig = i

In 2nd{2}^{nd} case,

igR0=(I−ig)S⇒(ig)2=(SRg+S)i{i}_{g}{R}_{0} = \left(I - {i}_{g}\right)S ⇒ {\left({i}_{g}\right)}_{2} = \left(\dfrac{S}{{R}_{g} + S}\right)i

If (ig)2=13(ig),⇒(SRg+S)i=13i{\left({i}_{g}\right)}_{2} = \dfrac{1}{3}\left({i}_{g}\right), ⇒ \left(\dfrac{S}{{R}_{g} + S}\right)i = \dfrac{1}{3}i

Rg=2S{R}_{g} = 2S

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