JEE Main202131 Aug 2021Evening ShiftPhysicsCurrent ElectricityActual
A resistor dissipates 192 J of energy in 1 s when a current of 4 A is passed through it. Now, when the current is doubled, the amount of thermal energy dissipated in 5 s is _____________ J .
Correct answer
0
Step-by-step solution
P = i 2 R t 192 = 4 × 4 × R × 1 R = 12 Ω P ' = i ' 2 R t ' = 8 × 8 × 12 × 5 = 3840   J