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JEE Main202126 Aug 2021Evening ShiftPhysicsCurrent ElectricityActual

If you are provided a set of resistances, 2 Ω , 4 Ω , 6 Ω and 8 Ω . Connect these resistances to obtain an equivalent resistance of 46 3 Ω .

Options

  1. A2   Ω and 6   Ω are in parallel with 4   Ω and 8   Ω in series
  2. B4   Ω and 6   Ω are in parallel with 2   Ω and 8   Ω in series
  3. C2   Ω and 4   Ω are in parallel with 6   Ω and 8   Ω in series
  4. D6   Ω and 8   Ω are in parallel with 2   Ω and 4   Ω in series

Correct answer

C. 2   Ω and 4   Ω are in parallel with 6   Ω and 8   Ω in series

Step-by-step solution

We can arrange the circuit like above now on solving we get a simplified circuit, here, both the resistance are connected in series then resultant resistance will be, R e q = 4 3   Ω + 14   Ω = 46 3   Ω , in the other case we can not get this result.

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