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JEE Main202126 Aug 2021Morning ShiftPhysicsCurrent ElectricityActual

In the given figure, the emf of the cell is 2 . 2 V and if internal resistance is 0 . 6 Ω . Calculate the power dissipated in the whole circuit:

Options

  1. A1.32   W
  2. B4 .4 W
  3. C0 . 65   W
  4. D2 . 2   W

Correct answer

D. 2 . 2   W

Step-by-step solution

The above circuit in the question is arranged like that, so all the resistance are connected in parallel and the net resistance of the parallel resistor becomes, 1 R P = 1 R 1 + 1 R 2 + 1 R 3 + 1 R 4 = 1 4 + 1 6 + 1 12 + 1 8 ⇒ R P = 48 30   Ω Now the net resistance will be, R n e t = 48 30 + 0 . 6   Ω , so the net power, P = V 2 R = ( 2 . 2 ) 2 2 . 2 = 2 . 2   W

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