In the given potentiometer circuit arrangement, the balancing length AC is measured to be 250 cm . When the galvanometer connection is shifted from point (1) to point (2) in the given diagram, the balancing length becomes 400 cm . The ratio

Question

In the given potentiometer circuit arrangement, the balancing length AC is measured to be 250 cm . When the galvanometer connection is shifted from point (1) to point (2) in the given diagram, the balancing length becomes 400 cm . The ratio of the emf of two cells &#949; 1 &#949; 2 is:

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Correct answer: A. 5 3

E 1 = k &#8467; 1 &#160; &#8230; ( 1 ) E 1 + E 2 = k &#8467; 2 &#160; &#8230; ( 2 ) E 1 E 1 + E 2 = &#8467; 1 &#8467; 2 = 250 400 = 5 8 8 E 1 = 5 E 1 + 5 E 2 3 E 1 = 5 E 2 E 1 E 2 = 5 3

In the given potentiometer circuit arrangement, the balancing length AC is measured to be 250 cm . When the galvanometer connection is shifted from point (1) to point (2) in the given diagram, the balancing length becomes 400 cm . The ratio of the emf of two cells ε 1 ε 2 is:

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Correct answer

Step-by-step solution

More from Current Electricity

In the given potentiometer circuit arrangement, the balancing length AC is measured to be 250 cm . When the galvanometer connection is shifted from point (1) to point (2) in the given diagram, the balancing length becomes 400 cm . The ratio of the emf of two cells &#949; 1 &#949; 2 is:

Options

Correct answer

Step-by-step solution

More from Current Electricity

In the given potentiometer circuit arrangement, the balancing length AC is measured to be 250 cm . When the galvanometer connection is shifted from point (1) to point (2) in the given diagram, the balancing length becomes 400 cm . The ratio of the emf of two cells ε 1 ε 2 is: