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JEE Main202125 Jul 2021Evening ShiftPhysicsCurrent ElectricityActual

The given potentiometer has its wire of resistance 10 Ω . When the sliding contact is in the middle of the potentiometer wire, the potential drop across 2 Ω resistor is:

Options

  1. A10   V
  2. B5   V
  3. C40 9   V
  4. D40 11   V

Correct answer

C. 40 9   V

Step-by-step solution

20 - V 0 5 + 0 - V 0 5 + 20 - V 0 2 = 0 4 + 10 = 2   V 0 5 + V 0 2 14 = 4   V 0 + 5   V 0 10 V 0 = 140 9 Volt Potential difference across 2   Ω resistor is 20 - V 0 That is 20 - 140 9 V Hence, answer is 40 9 Volt

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