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JEE Main202125 Jul 2021Morning ShiftPhysicsCurrent ElectricityActual

In the given figure, there is a circuit of potentiometer of length A B = 10 m . The resistance per unit length is 0 . 1 Ω per cm . Across A B , a battery of emf E and internal resistance r is connected. The maximum value of emf measured by this potentiometer is:

Options

  1. A5   V
  2. B2 . 25   V
  3. C6   V
  4. D2 . 75   V

Correct answer

A. 5   V

Step-by-step solution

Maximum voltage that can be measured by this potentiometer will be equal to potential drop across A B , R AB = 10 × 0 . 1 × 100 = 100   ohm ∴   V AB = 6 20 + 100 × 100 = 6 × 100 120 = 5   V

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