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JEE Main202124 Feb 2021Morning ShiftPhysicsCurrent ElectricityActual

A cell E 1 of emf 6 V and internal resistance 2 Ω is connected with another cell E 2 of emf 4 V and internal resistance 8 Ω (as shown in the figure). The potential difference across points X and Y is:

Options

  1. A10 . 0   V
  2. B5 . 6   V
  3. C2 . 0   V
  4. D3 . 6   V

Correct answer

B. 5 . 6   V

Step-by-step solution

I = 6 - 4 10 = 1 5   A   V x + 4 + 8 × 1 5 - V y = 0   V x - V y = - 5 . 6 ⇒ V x - V y = 5 . 6   V

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