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JEE Main201912 Apr 2019Morning ShiftPhysicsCurrent ElectricityActual

To verify Ohm’s law, a student connects the voltmeter across the battery as shown in the figure. The measured voltage is plotted as a function of the current, and the following graph is obtained: If V o is almost zero, identify the correct statement:

Options

  1. AThe emf of the battery is 1.5 V and its internal resistance is 1.5 Ω
  2. BThe value of the resistance R is 1.5 Ω
  3. CThe potential difference across the battery is 1.5 V when it sends a current of 1000 m A
  4. DThe emf of the battery is 1.5 V and the value of R is 1.5 Ω

Correct answer

A. The emf of the battery is 1.5 V and its internal resistance is 1.5 Ω

Step-by-step solution

V = E - I r when V = V 0 = 0 ⇒ 0 = E - I r ∴   E = I r when I = 0 ,   V = E = 1 . 5   V ∴   r = 1 . 5   Ω .

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