A galvanometer of resistance 100 Ω has 50 divisions on its scale and has sensitivity of 20 μ A / d i v i s i o n . It is to be converted to voltmeter with three ranges, of 0 - 2 V , 0 - 10 V and 0 - 20 V . The appropriate circuit to do so is:

Step-by-step solution

Given, the resistance of the galvanometer G = 100   Ω No. of divisions = 50 Current Sensitivity = 20   μ A / d i v i s i o n The maximum current through galvanometer will be I m a x = 50 × 20 × 10 - 6 = 10 - 3   A For V 1   =   2   V using Ohm's law V 1 =   I m a x   G + R 1 2 = 10 - 3   × 100 + R 1 ∴ R 1 = 1900   Ω For V 2   =   10   V using Ohm's law V 2   = I m a x G + R 1 + R 2 10 = 10 - 3 &#160