JEE Main201912 Apr 2019Morning ShiftPhysicsCurrent ElectricityActual
The resistive network shown below is connected to a D . C . source of 16 V . The power consumed by the network is 4 Watt. The value of R is:
Options
- A16 Ω
- B8 Ω
- C6 Ω
- D1 Ω
Correct answer
B. 8 Ω
Step-by-step solution
R e q for mixed series and parallel combination of given circuit R e q = 1 1 4 R + 1 4 R + R + 1 1 6 R + 1 12 R + R R e q = 8 R Power dissipated by circuit P = V 2 R e q ⇒ 4 = 16 2 8 R ⇒ R = 256 32 = 8   Ω