JEE Main20199 Apr 2019Evening ShiftPhysicsCurrent ElectricityActual
In a conductor, if the number of conduction electrons per unit volume is 8.5 × 10 28    m - 3 and mean free time is 25   f s (femto second), it’s approximate resistivity is: m e = 9.1 × 10 - 31   k g
Options
- A10 - 7 Ω m
- B10 - 6 Ω m
- C10 - 5 Ω m
- D10 - 8 Ω m
Correct answer
D. 10 - 8 Ω m
Step-by-step solution
We know i = n e Av d ⇒ i = V R = V A ρ l = E A ρ ρ = E A i = E A n e Av d Drift velocity can be written as v d = e E m e τ ρ = E A m e n e A e E τ = m e n e 2 τ = 9.1 × 1 0 - 31 8.5 × 1 0 28 × 1.6 × 10 - 19 2 × 25 × 1 0 - 15 ≈ 1.65 × 1 0 - 8   Ω   m