In the given circuit the internal resistance of the 18 V cell is negligible. If R 1 = 400 Ω , R 3 = 100 Ω and R 4 = 500 Ω and the reading of an ideal voltmeter across R 4 is 5 V , then the value of R 2 will be:

Step-by-step solution

Given reading of an ideal voltmeter for resistance R 4 is V 4   =   5   V , then current (let i 1 )is given branch (as resistance R 3 in series with resistance R 4 ) is i 1 = V R 4 = 5 500 = 0 . 01   A Then for resistance R 3 , the potential difference will be V 3   =   i 1   R 3   = 0 . 01 × 100   = 1 V So, for given branch of resistance potential difference is V 3   +   V 4   =   1   +   5   = 6   V From figure for resistanc