Drift speed of electrons, when 1.5 A current flows in a copper wire of cross section 5 mm 2 is v d . If the electron density in copper is 9 × 10 28 m - 3 the value of v d in mm s - 1 is close to (Take charge of an electron to be = 1.6 × 10 - 19 C )

Step-by-step solution

Given, Current, i = 1 . 5   A , Cross-section of the wire, A = 5 × 10 - 6   m 2 and Electron density, n = 9 × 10 28   m - 3 . As current, i = n e A v d ⇒ 1.5 = 9 × 10 28 × 1.6 × 10 - 19 × 5 × 10 - 6 × v d ⇒ v d = 0.02   mm   s - 1 .