JEE Main2018PhysicsCurrent ElectricityActual
A heating element has a resistance of 100 Ω at room temperature. When it is connected to a supply of 220 V , a steady current of 2 A passes in it and temperature is 500 o C more than the room temperature. The temperature coefficient of resistance of the heating element is
Options
- A5   × 10 - 4     o C - 1
- B2   × 10 - 4     o C - 1
- C1   × 10 - 4     o C - 1
- D0.5   × 10 - 4     o C - 1
Correct answer
B. 2   × 10 - 4     o C - 1
Step-by-step solution
Resistance of heating element after temperature increases by 500   o C = 220 2 = 110   Ω (from Ohm's law). The new resistance is related to the temperature coefficient of the heating element as 110 = 100   ( 1 + α 500 ) α = 10 100   × 500 ⇒ α = 2   × 10 - 4   ° C - 1