JEE Main2018PhysicsCurrent ElectricityActual
Two batteries with e.m.f. 12 V and 13 V are connected in parallel across a load resistor of 10 Ω . The internal resistance of the two batteries are 1 Ω and 2 Ω respectively. The voltage across the load lies between,
Options
- A11 . 7   V and 11 . 8   V
- B11 . 6   V and 11 . 7   V
- C11 . 5   V and 11 . 6   V
- D11 . 4   V and 11 . 5   V
Correct answer
C. 11 . 5   V and 11 . 6   V
Step-by-step solution
As shown in figure two cells are connected in parallel with the load resistance of R = 10   Ω . Let current i 1 ,   i 2 drawn from both cells as shown, from K . C . L . i   =   i 1 +   i 2     . . . 1 Apply K . V . L . for loop A C D F , E 1 - i   R - i 1   r 1 = 0 ⇒ 12 - 10 i - i 1 = 0     . . . 2 From equations 1 and 2 12 - 11   i 1 - 10 i 2 = 0     . . . 3 Now, for loop B C D E , Apply K . V . L . E 2 - 10 i - i 2 r 2 = 0 ⇒ 13