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Four bulbs B 1 , B 2 , B 3 and B 4 of 100 W each are connected to 220 V main as shown in the figure. The reading in an ideal ammeter will be

Options

  1. A0 . 90   A
  2. B1 . 35   A
  3. C0 . 45   A
  4. D1 . 80   A

Correct answer

B. 1 . 35   A

Step-by-step solution

The resistance of any bulb = V 2 / P Current through ammeter at shown position = 3 i 1 current in any 1 bulb = i 1 = V R = V V 2 / P = P V = 1 0 0 2 2 0 Through ammeter, ⇒ i net = 3 i 1 = 3 0 0 2 2 0 = 1 .35   A

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