Six equal resistances are connected between points P , Q and R as shown in figure. Then net resistance will be maximum between :

Step-by-step solution

Resistance between P and Q r_ PQ =r₁₁ ( r 3 + r 2 )= r 5 6 r r+ 5 6 r = 5 11 r Resistance between Q and R r _ QR = r 2 11 ( r + r 3 )= r 2 4 3 r r 2 + 4 3 r = 4 11 r Resistance between P and R r _ PR = r 3 l ( r 2 + r )= r 3 3 2 r r 3 + 3 2 r = 3 11 r Hence, it is clear that r _ PQ is maximum