JEE Main2012PhysicsCurrent ElectricityActual
In an experiment of potentiometer for measuring the internal resistance of primary cell a balancing length is obtained on the potentiometer wire when the cell is open circuit. Now the cell is short circuited by a resistance R . If R is to be equal to the internal resistance of the cell the balancing length on the potentiometer wire will be
Options
- A2
- B/ 2
- C/ 4
Correct answer
C. / 4
Step-by-step solution
Balancing length l will give emf of cell E=K l Here K is potential gradient. If the cell is short circuited by resistance 'R' Let balancing length obtained be l^ then aligned & V=k l^ & r= ( E-V V ) R & V=E-V & 2 V=E or, & 2 K l^ =K l & l^ = l 2 aligned