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A 6.0 volt battery is connected to two light bulbs as shown in figure. Light bulb 1 has resistance 3 ohm while light bulb 2 has resistance 6 ohm . Battery has negligible internal resistance. Which bulb will glow brighter?

Options

  1. ABulb 1 will glow more first and then its brightness will become less than bulb 2
  2. BBulb 1
  3. CBulb 2
  4. DBoth glow equally

Correct answer

B. Bulb 1

Step-by-step solution

Total resistance = 6 3 6+3 =2 Current in circuit = 6 2 =3 A Therefore current through bulb 1 is 2 ~A and bulb 2 is 1 A . So bulb 1 will glow more.

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