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A 5 ~V battery with internal resistance 2 and a 2 ~V battery with internal resistance 1 are connected to a 10 resistor as shown in the figure. The current in the 10 resistor is

Options

  1. A0.27 A P₂ to P₁
  2. B0.03 A P₁ to P₂
  3. C0.03 A P₂ to P₁
  4. D0.27 ~A P P₁ to P₂

Correct answer

C. 0.03 A P₂ to P₁

Step-by-step solution

aligned & V_ P₂ -V_ P₁ = 5 2 + 0 10 - 2 1 1 2 + 1 10 + 1 1 & I= V_ P₂ -V_ P₁ 10 =0.03 from P₂ P₁ aligned

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