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In a Wheatstone's bridge, there resistances P , Q and R connected in the three arms and the fourth arm is formed by two resistances S ₁ and S ₂ connected in parallel. The condition for bridge to be balanced will be

Options

  1. AP Q = R S ₁+ S ₂
  2. BP Q = 2 R S ₁+ S ₂
  3. CP Q = R ( S ₁+ S ₂ ) S ₁ ~S ₂
  4. DP Q = R ( S ₁+ S ₂ ) 2 ~S ₁ ~S ₂

Correct answer

C. P Q = R ( S ₁+ S ₂ ) S ₁ ~S ₂

Step-by-step solution

P Q = R ( S ₁+ S ₂ ) S ₁ ~S ₂

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