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JEE Main202529 Jan 2025Morning ShiftPhysicsElectromagnetic InductionActual

Consider ( I ₁ ) and ( I ₂ ) are the currents flowing simultaneously in two nearby coils 1 & 2, respectively. If ( L ₁= ) self inductance of coil (1, M ₁₂= ) mutual inductance of coil 1 with respect to coil 2, then the value of induced emf in coil 1 will be Options

Options

  1. A( ₁=-L₁ dI ₂ d t - M ₁₂ dI ₁ d t )
  2. B( ₁=-L₁ dI ₁ d t - M ₁₂ dI ₂ d t )
  3. C( ₁=-L₁ dI ₁ d t - M ₁₂ dI ₁ d t )
  4. D( ₁=-L₁ dI ₁ d t + M ₁₂ dI ₂ dt )

Correct answer

B. ( ₁=-L₁ dI ₁ d t - M ₁₂ dI ₂ d t )

Step-by-step solution

aligned & ₁= L ₁ I ₁+ M ₁₂ I ₂ & ₁=- d ₁ dt =- L ₁ dI 1 I ₁₂ dt - M ₁₂ ~d I₂ dt aligned

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