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JEE Main202528 Jan 2025Evening ShiftPhysicsElectromagnetic InductionActual

A uniform magnetic field of 0.4 T acts perpendicular to a circular copper disc 20 cm in radius. The disc is having a uniform angular velocity of 10 rad s ⁻¹ about an axis through its centre and perpendicular to the disc. What is the potential difference developed between the axis of the disc and the rim ? ( =3.14)

Options

  1. A0.5024 ~V
  2. B~V
  3. C0.2512 ~V
  4. D0.1256 ~V

Correct answer

C. 0.2512 ~V

Step-by-step solution

aligned & B =0.4 ~T & r =20 ~cm & =10 rad / s & E = 1 2 ~B R ^2 & =0.2512 ~V aligned

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