A rectangular loop of length 2 . 5m and width 2m is placed at 60 °...

The formula to calculate the change in the magnetic flux associated with the given loop can be written as

$\begin{cases}∆ ϕ & = & - BAcos\theta \\ & = & - B\left(lb\right)cos\theta . . . \left(1\right)\end{cases}$

The formula to calculate the induced emf is given by

$\begin{cases}ε & = & - \dfrac{∆ ϕ}{∆ t} \\ & = & \dfrac{B\left(lb\right)cos\theta}{∆ t} . . . \left(2\right)\end{cases}$

From equation (2), it follows that

$\begin{cases}ε & = & \dfrac{4 \times \left(2 . 5 \times 2\right) \times \cos 60 °}{10}V \\ & = & 1V\end{cases}$