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JEE Main202427 Jan 2024Morning ShiftPhysicsElectromagnetic InductionActual

A rectangular loop of length 2 . 5 m and width 2 m is placed at 60 ° to a magnetic field of 4 T . The loop is removed from the field in 10 sec . The average emf induced in the loop during this time is

Options

  1. A- 2 V
  2. B+ 2 V
  3. C+ 1 V
  4. D- 1 V

Correct answer

C. + 1 V

Step-by-step solution

The formula to calculate the change in the magnetic flux associated with the given loop can be written as ∆ ϕ = - B A cos θ = - B l b cos θ . . . 1 The formula to calculate the induced emf is given by ε = - ∆ ϕ ∆ t = B l b cos θ ∆ t . . . 2 From equation (2), it follows that ε = 4 × 2 . 5 × 2 × cos 60 ° 10 V = 1 V

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