Two coils have mutual inductance 0 . 002 H . The current changes in the first coil according to the relation i = i 0 s i n ω t , where i 0 = 5 A and ω = 50 π rad s - 1 . The maximum value of emf in the second coil is π α V . The value of α is

Step-by-step solution

The amount of flux induced in the second coil due to the first one is given by ϕ 2 = M i = M i 0 s i n ω t . . . 1 where, M is the mutual inductance of the coils. The formula to calculate the emf induced can be written as ε = - d ϕ 2 d t . . . 2 From equation (2), it follows that, ε max = M i 0 ω = 0 . 002 × 5 × 50 π V = π 2 V Hence, α = 2 .