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JEE Main 20236 AprilMorning Shift
Exam
JEE Main
Year
2023
Date
6 April
Shift
Morning Shift
Subject
Physics
Chapter
Electromagnetic Induction

JEE Main 2023 · 6 April · Morning Shift · Physics · Electromagnetic Induction

For the plane electromagnetic wave given by E = E _ 0 ( – kx ) and...

For the plane electromagnetic wave given by E=E0sin⁡(\omegat–kx)E = {E}_{0}\sin ( \omegat – kx ) and B=B0sin⁡(\omegat−kx),B = {B}_{0}\sin ( \omegat - kx ) , the ratio of average electric energy density to average magnetic energy density is

Options

  1. A12\dfrac{1}{2}
  2. B22
  3. C44
  4. D11

Correct answer

D. 11

Step-by-step solution

The formula to calculate the average electric energy density is given by

UE=12ε0E2...(1){U}_{E} = \dfrac{1}{2}{ε}_{0}{E}^{2} . . . ( 1 )

and, the formula to calculate average magnetic energy density is given by

UB=12μ0B2...(2){U}_{B} = \dfrac{1}{2{\mu}_{0}}{B}^{2} . . . ( 2 )

For any particular electromagnetic wave, both magnetic and electric field are equally involved in contributing to energy density. Hence, the ratio of average electric energy density to magnetic energy density is 11.

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