JEE Main202228 Jul 2022Evening ShiftPhysicsElectromagnetic InductionActual
For the given circuit the current through battery of 6 V just after closing the switch ' S ' will be _____ A .
Correct answer
0
Step-by-step solution
Just after closing the switch S , inductor behaves like an open circuit, so no current will flow through 2   Ω resistors. Thus, current through the circuit is I = 6 2 + 4 = 1   A (Here 2   Ω and 4   Ω resistors are in series).