Two coils of self inductance L _ 1 and L _ 2 are connected in series combination having mutual inductance of the coils as M . The equivalent self inductance of the combination will be

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Correct answer: B. L _ 1 + L _ 2 - 2M

Two coils of self inductance L _ 1 and L _ 2 are connected in series combination having mutual inductance of the coils

Here self inductances are in series but their mutual inductances are linked oppositely.

As the inductors connected are in series opposition, hence magnetic flux will be opposing each other. Therefore,

${L}_{eq} = {L}_{1} + {L}_{2} - 2M$

Two coils of self inductance L _ 1 and L _ 2 are connected in...

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