JEE Main202226 Jun 2022Evening ShiftPhysicsElectromagnetic InductionActual
A metallic conductor of length 1 m rotates in a vertical plane parallel to east-west direction about one of its end with angular velocity 5 rad s - 1 . If the horizontal component of earth's magnetic field is 0 . 2 × 10 - 4 T , then emf induced between the two ends of the conductor is
Options
- A5 μ V
- B50 μ V
- C5   m V
- D50   m V
Correct answer
B. 50 μ V
Step-by-step solution
Given here, B H = 0 . 2 × 10 - 4   T , ω = 5   rad   s - 1 and l =   1   m . Emf induced in a rotating conducting rod is given by, ε = 1 2 B ω l 2 Substituting the given values, we obtain ε = 1 2 × 0 . 2 × 10 - 4 × 5 × 1 2 = 0 . 5 × 10 - 4   V = 50   μV