A metallic conductor of length 1m rotates in a vertical plane...

Given here, ${B}_{H} = 0 . 2 \times {10}^{- 4}T$, $\omega = 5rad{s}^{- 1}$ and $l = 1m$.

Emf induced in a rotating conducting rod is given by,

$ε = \dfrac{1}{2}B\omega{l}^{2}$

Substituting the given values, we obtain

$ε = \dfrac{1}{2} \times 0 . 2 \times {10}^{- 4} \times 5 \times {\left(1\right)}^{2} = 0 . 5 \times {10}^{- 4}V = 50\mu V$