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JEE Main202126 Aug 2021Evening ShiftPhysicsElectromagnetic InductionActual

A circular coil of radius 8 . 0 cm and 20 turns is rotated about its vertical diameter with an angular speed of 50 rad s - 1 in a uniform horizontal magnetic field of 3 . 0 × 10 - 2 T . The maximum emf induced in the coil will be _______ × 10 - 2 volt (rounded off to the nearest integer).

Correct answer

0

Step-by-step solution

Emf = B ω NAsin ω t Emf max = BωNA = BωN πR 2 = 3 × 10 - 2 × 50 × 20 × π × 64 10 4 ≈ 60 × 10 - 2   V

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