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JEE Main 202126 AugustEvening Shift
Exam
JEE Main
Year
2021
Date
26 August
Shift
Evening Shift
Subject
Physics
Chapter
Electromagnetic Induction

JEE Main 2021 · 26 August · Evening Shift · Physics · Electromagnetic Induction

A circular coil of radius 8 . 0cm and 20 turns is rotated about its...

A circular coil of radius 8.0cm8 . 0cm and 2020 turns is rotated about its vertical diameter with an angular speed of 50rads−150rad{s}^{- 1} in a uniform horizontal magnetic field of 3.0×10−2T3 . 0 \times {10}^{- 2}T. The maximum emf induced in the coil will be _______×10−2\times {10}^{- 2} volt (rounded off to the nearest integer).

Correct answer

0

Step-by-step solution

Emf = B\omega NAsin\omegat</p><p></p><p>{Emf}_\max = B \omega NA = B \omega N\left({\pi R}^{2}\right)</p><p></p><p>= \left(3 \times {10}^{- 2}\right) \times \left(50\right) \times \left(20\right) \times \left(\pi \times \dfrac{64}{{10}^{4}}\right) \approx 60 \times {10}^{- 2}V

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