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JEE Main 202127 JulyEvening Shift
Exam
JEE Main
Year
2021
Date
27 July
Shift
Evening Shift
Subject
Physics
Chapter
Electromagnetic Induction

JEE Main 2021 · 27 July · Evening Shift · Physics · Electromagnetic Induction

In the given figure the magnetic flux through the loop increases...

In the given figure the magnetic flux through the loop increases according to the relation ϕB(t)=10t2+20t{ϕ}_{B} ( t ) = 10{t}^{2} + 20t, where ϕB{ϕ}_{B} is in milliwebers and tt is in seconds. The magnitude of current through R=2ΩR = 2Ω resistor at t=5st = 5s is _____ mA.mA .

In the given figure the magnetic flux through the loop increases according to the relation ϕ _ B ( t ) = 10 t ^ 2 + 20t

Correct answer

0

Step-by-step solution

∣ϵ∣=dϕdt=20t+20mV| ϵ | = \dfrac{dϕ}{dt} = 20t + 20mV

∣i∣=∣ϵ∣R=10t+10mA| i | = \dfrac{| ϵ |}{R} = 10t + 10mA

At t=5t = 5

∣i∣=60mA| i | = 60mA

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