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JEE Main202127 Jul 2021Evening ShiftPhysicsElectromagnetic InductionActual

In the given figure the magnetic flux through the loop increases according to the relation ϕ B ( t ) = 10 t 2 + 20 t , where ϕ B is in milliwebers and t is in seconds. The magnitude of current through R = 2 Ω resistor at t = 5 s is _____ mA .

Correct answer

0

Step-by-step solution

| ϵ | = d ϕ d t = 20 t + 20   mV | i | = | ϵ | R = 10 t + 10   mA At t = 5 | i | = 60   mA

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