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JEE Main 202116 MarchEvening Shift
Exam
JEE Main
Year
2021
Date
16 March
Shift
Evening Shift
Subject
Physics
Chapter
Electromagnetic Induction

JEE Main 2021 · 16 March · Evening Shift · Physics · Electromagnetic Induction

The magnetic field in a region is given by → B = B _ 0 ((x)/(a)) ^...

The magnetic field in a region is given by \overset{\to}{B} = {B}_{0}\left(\dfrac{x}{a}\right)\overset{^}{k}. A square loop of side d is placed with its edges along the xx and yy axes. The loop is moved with a constant velocity \overset{\to}{v} = {v}_{0}\overset{^}{i}. The emf induced in the loop is :

The magnetic field in a region is given by → B = B _ 0 ((x)/(a)) ^ k . A square loop of side d is placed with its edges

Options

  1. AB0v02d2a\dfrac{{B}_{0}{v}_{0}^{2}d}{2a}
  2. BB0v0d2a\dfrac{{B}_{0}{v}_{0}d}{2a}
  3. CB0v0d2a\dfrac{{B}_{0}{v}_{0}{d}^{2}}{a}
  4. DB0v0d22a\dfrac{{B}_{0}{v}_{0}{d}^{2}}{2a}

Correct answer

C. B0v0d2a\dfrac{{B}_{0}{v}_{0}{d}^{2}}{a}

Step-by-step solution

E1=B0(x+d)av0d{E}_{1} = \dfrac{{B}_{0}\left(x + d\right)}{a}{v}_{0}d

E2=B0(x)av0d{E}_{2} = \dfrac{{B}_{0}\left(x\right)}{a}{v}_{0}d

Enet=E1−E2{E}_{net} = {E}_{1} - {E}_{2}

Enet=B0v0d2a{E}_{net} = \dfrac{{B}_{0}{v}_{0}{d}^{2}}{a}

The magnetic field in a region is given by → B = B _ 0 ((x)/(a)) ^ k . A square loop of side d is placed with its edges

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