Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
JEE Main202116 Mar 2021Morning ShiftPhysicsElectromagnetic InductionActual

A conducting bar of length L is free to slide on two parallel conducting rails as shown in the figure Two resistors R 1 and R 2 are connected across the ends of the rails. There is a uniform magnetic field B → pointing into the page. An external agent pulls the bar to the left at a constant speed v . The correct statement about the directions of induced currents I 1 and I 2 flowing through R 1 and R 2 respectiv

Options

  1. ABoth I 1 and I 2 are in anticlockwise direction
  2. BBoth I 1 and I 2 are in clockwise direction
  3. CI 1 is in clockwise direction and I 2 is in anticlockwise direction
  4. DI 1 is in anticlockwise direction and I 2 is in clockwise direction

Correct answer

C. I 1 is in clockwise direction and I 2 is in anticlockwise direction

Step-by-step solution

Given, the external agent pulls the bar towards left. According to Lenz's law and Fleming's right hand rule, there will be a motional EMF generated in the bar. The right-hand rule tells us that the magnetic force on positive charges will be in downward direction and the electric equivalent circuit can be drawn as shown below. So, I 1 is in the clockwise direction and I 2 is in the anticlockwise direction.

Practice Electromagnetic Induction on Quantrex Academy →

More from Electromagnetic Induction

List-I contains four conducting loops lying in the XY plane, as shown in the figures. The loops are rotating about Z axis passing through the point O with time period T in clockwis 2026A 30 cm long solenoid has 10 turns per cm and area of 5 cm ^2 . The current through the solenoid coil varies from 2 A to 4 A in 3.14 s. The e.m.f. induced in the coil is 10⁻⁵ V. Th 2026A square loop of side 2 cm is placed in a time varying magnetic field with magnitude as B = 0.4 (300t) Tesla. The normal to the plane of loop makes an angle of 60° with the field. 2026An inductor of inductance 10 mH having resistance of 100 , is connected to battery of E.M.F. 1.0 V through a switch as shown in the figure below. After switch is closed, the ratio 2026A metal rod of length L rotates about one end at origin with a uniform angular velocity . The magnetic field radially falls off as B(r) = B₀ e^ - r ; being a positive constant. The 2026A circular loop of radius 20 cm and resistance 2 is placed in a time varying magnetic field B = (2t^2 + 2t + 3) T . At t = 0 , for the plane of the loop being perpendicular to the 2026In the given circuit below inductance values of L₁ , L₂ and L₃ are same. The magnetic energy stored in the entire circuit is (U_t) and that stored in the L₂ inductor is (U_l) . U_t 2026A circular current loop of radius R is placed inside square loop of side length L(L >> R) such that they are co-planar and their centers coincide. The permeability of free space is 2026 Full Electromagnetic Induction list All JEE Main PYQs